A line graph is used.

The number of victims.

The number of victims decreases, except for the peak years 1976 en 1979. To study exact numbers you should use the table. The graph shows the trend better.

You should compare the numbers of victims to the total size of the population for a better understanding.

The number of burn victims was 5325. There is a total population of $\frac{5325}{2.3}\times 100000=231521739$ in the USA.

$\mathrm{height}$ and $\mathrm{age}$

$\mathrm{weight}$ and $\mathrm{height}$

The graphs show the average development of height and weight of a child over time.

In the bottom half you read out the height on the P₅₀ line (approximately 170 cm). In the top graph you can read out the weight between the P₁₀ and P₉₀ lines correponding to < 20 years (approximately 60 kg).

Just do it.

Marleen is slightly taller than average. Her weight is about average.

The water level changes continuously.

Vase $1$ belongs to graph 2.
Vase $2$ belongs to graph 4.
Vase $3$ belongs to graph 3.
Vase $4$ belongs to graph 1.

All graphs reach the level of 20 cm in half the time .

De period is exactly $1$ year.

Nature is blooming in this period and there is a lot of green foliage. So more CO₂ is transformed into O₂.

The minimum was $348$ m³. And the maximum $360$ m³.

The total volume of air remains approximately equal. The plants determine whether there is a lot of carbondioxide (and less oxygen) or little carbondioxide (and more oxygen) in the air.

Trend line ratio oxygen/nitrogen passes through $-80$ in jan.1989 and $-150$ in jan.1992.

Trend line CO₂ passes through 352 p.p.m.v. in jan.1989 and 356 p.p.m.v. in jan.1992. Yes, when less CO₂ is changed into O₂ the amount of CO₂ increases and the amount of O₂ decreases. This could be the result of deforestation of the tropical rainforests.

Per $3$ years there will be an increase of $4$ p.p.m.v. CO₂

$8$ $356+\frac{8}{3}\cdot 4=366\frac{2}{3}$